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Fyneman exercise I ch31-4

Q. It was deduced that the instantaneous energy flux of a wave is watts per square meter: Find the total rate at which energy is radiated by an electron which is oscillating with amplitude and angular frequency . Compare the energy radiated per cycle with the stored energy , and thus find the damping constant . This process is called radiation damping An excited atom gives out radiation having a certain wavelength . Calculate theoretically the expected breadth of the spectral line, if the breadth arises solely from radiation damping. (Think of the atom as being a tiny damped oscillator having a large Q.) A. 1. What is by an electron? Let position and time , referring FLP Volume I Chapter 28 , where is angle between sight line(i.e position vector r) and oscillation deriction. Electron oscillates with amplitude , angular frequency , so retarded acceleration is Then is What is ? At position Total rate at which energy is radiated by an...

Fyneman exercise I ch31-3

Q. Noting that the electric field of a light wave traveling throgh a medium of refractive index is , a) show that, if , b) use the equation to find the rate at which the intensity of a beam of radiation whose frequency is exactly equal to the natural frequency of an atom is attenuated. A. a) Substitute , b) , , where and So, attenuation rate of intensity is

Fyneman exercise I ch31-1

Q. Find the index of refraction of Aluminum for x-rays of wavelength . Assume that all of the electrons in Aluminum have natural frequencies very much less than the frequency of the x-rays. A. Index of refraction eq.(31-19) symbol meaning value m mass of electron kilograms charge of electron coulombs Vacuum permittivity F/m Number of charges per unit volume see below. Aluminum properties molar mass density atomic number Ref Avogadro constant number of charges in unit volume Number of charges per unit volume can be thought and where, density = molar mass = Angular frequency resonance frequency is negligible. Problem state natural frequencies very much less than the frequency of the x-rays So, index of refraction is result